$y=2x+5$

$x_1$

$x_2$

f(x) = ((2 * x^(2)) + x - 3) / (x - 2)
i: y = (2 * x) + 5
A: (0, 3 / 2)
B: (-3 / 2, 0)
C: (1, 0)
AB: (2 - sqrt(14) / 2, 9 - (2 * sqrt(14)))
D = (2.61261842978511, -0.21119478089472293)
j = Tangent(AB, f)
AC: (2 + sqrt(14) / 2, 9 + (2 * sqrt(14)))
k = Tangent(AC, f)